1,3x^2=4800

Solution for 1,3x^2=4800 equation:

1.3x^2=4800

We move all terms to the left:

1.3x^2-(4800)=0

a = 1.3; b = 0; c = -4800;
Δ = b2-4ac
Δ = 02-4·1.3·(-4800)
Δ = 24960
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{24960}=\sqrt{64*390}=\sqrt{64}*\sqrt{390}=8\sqrt{390}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{390}}{2*1.3}=\frac{0-8\sqrt{390}}{2.6}
=-\frac{8\sqrt{390}}{2.6}
=-\frac{4\sqrt{390}}{1.3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{390}}{2*1.3}=\frac{0+8\sqrt{390}}{2.6}
=\frac{8\sqrt{390}}{2.6}
=\frac{4\sqrt{390}}{1.3}
$